Find the 15th term of the A.P. with the second term by 11 and common difference 9.
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15 term=128
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It helps you to do other problems
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jhalak23:
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Answered by
1
given 2nd term equal to 11
and common difference=9
so,
a+d=11
a+9=11
a=11-9
a=2
Now the 15th term=a+14d
2+14×9
2+126
= 128
hope it will help you
and common difference=9
so,
a+d=11
a+9=11
a=11-9
a=2
Now the 15th term=a+14d
2+14×9
2+126
= 128
hope it will help you
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