Math, asked by krittikaseth, 4 months ago

find the 16th term of an ap if the first term is 2 and the common difference is 3, the second term is 5 ​

Answers

Answered by vipashyana1
0

Answer:

16th term=47

Step-by-step explanation:

a=2, d=3, n=16

An=a+(n-1)d

A16=2+(16-1)3

A16=2+(15)3

A16=2+45

A16=47

Therefore, the 16th term of an AP is 47.

Answered by priyanshunigam75
0

Answer:

Answer:

Given

A body of mass 500 kg started from rest and moves with a speed of 10 m/s in 5 s

To Find

Force

Solution

We know that

\rm \longrightarrow F=m \times a⟶F=m×a

\rm \longrightarrow a=\bigg(\dfrac{v-u}{t}\bigg)⟶a=(

t

v−u

)

Therefore

\rm \longrightarrow F=m \times \bigg(\dfrac{v-u}{t}\bigg)⟶F=m×(

t

v−u

)

Here

F = Force

m = Mass

a = Acceleration

u = Initial velocity

v = Final velocity

t = Time

Units

F = Newton (N)

m = kilogram (kg)

a = metre/square second (m/s²)

u = metre/second (m/s)

v = metre/second (m/s)

t = second (s)

According to the question

We are asked to find the force

Therefore

We must find "F"

Given that

A body of mass 500 kg started from rest and moves with a speed of 10 m/s in 5 s

Hence

m = 500 kg

u = 0 m/s [starts from rest]

v = 10 m/s

t = 5 s

Substituting the values

We get

\rm \longrightarrow F=500 \times \bigg(\dfrac{10-0}{5}\bigg) \ N⟶F=500×(

5

10−0

) N

\rm \longrightarrow F=500 \times \bigg(\dfrac{10}{5}\bigg) \ N⟶F=500×(

5

10

) N

\rm \longrightarrow F=100 \times 10 \ N⟶F=100×10 N

Therefore

\rm \longrightarrow F=1000 \ N⟶F=1000 N

Hence

Force = 1000 N

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