find the 16th term of ap 3 5 7 9
Answers
Answered by
2
a16=a+(n-1).d
a16=3+(16-1).2
a16=3+15*2
a16=3+30
a16=33
Answered by
0
Answer:
33
Step-by-step explanation:
1st term(a)- 3
2nd term - 5
Common difference (d) = (3-5) = 2
n= 16
therefore
16th term of the ap series = a+(n-1)*d
=3+(16-1)*d
=3+(15*2)
=3+30
=33
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