Question

Find the 16th term of AP 3,5,7,9...​

Answer 1

Answer:

The given AP is 3, 5, 7, 9, 11, …

Its first term = 3 and common difference = (5-3) = 2.

∴ a= 3 and d = (5-3) = 2.

(i) Its nth term is given by

Tn=a+(n-1)d

=3+(n-1)×2=(2n+1)[∵a=3andd=2].

∴nth term=(2n+1)

(ii) 16th term of the given AP is

T16=a+(16-1)d=(a+15d)

=(3+15×2)=33[∵a=3andd=2]

∴ 16th term = 33

Step-by-step explanation:

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Answer 2

Answer:

formula =

$a + (n - 1)d$

a=3

d=5-3=2

16th term=

$3 + (16 - 1) \times 2$

=3+2x15

=3+30

=33

Therefore the 16th term is 33

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