Question

find the 16th term of AP, whose first term is 6 and comman difference is 3​

Answer 1

Answer:

given that

nth term = 16

first term a = 6

common difference d = 3

According to the question

Tn = a + ( n - 1 ) d

= 6 + ( 16 - 1 ) 3

= 6 + 15 × 3

= 6 + 45

= 51

therefore the 16th term of the AP is 51.

Answer 2

Answer:

a=3

Tn=a+(n-1)d

T16=6+(16-1)d

=6+15(3)

=6+45

=51.