Question

Find the 16th term of the A.P.7,11,15,19....Find the sum of the first 6 terms

Answer 1

=a+(n-1)d
=7+(16-1)4
=7+60
=67

16th term=67


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Sum will be

=n/2(2a+(n-1)d)
=6/2(2×7+(6-1)4)
=3(14+20)
=3(34)
=102

Answer 2

Here is your answer ⤵⤵⤵⤵⤵⤵

a = 7

d = 4

a16 = a+15d

= 7+15x4

= 7+60

= 67


S6 = n/2{2a+(n-1)d}

= 6/2{2x7+(6-1)4}

= 3{14+5x4)}

= 3(14+20)

= 3(34)

= 102




HOPE IT HELPS YOU ☺☺ !!