Find the 16th term of the A.P.7,11,15,19....Find the sum of the first 6 terms
Answers
Answered by
5
=a+(n-1)d
=7+(16-1)4
=7+60
=67
16th term=67
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Sum will be
=n/2(2a+(n-1)d)
=6/2(2×7+(6-1)4)
=3(14+20)
=3(34)
=102
=7+(16-1)4
=7+60
=67
16th term=67
===
===
===
Sum will be
=n/2(2a+(n-1)d)
=6/2(2×7+(6-1)4)
=3(14+20)
=3(34)
=102
Answered by
2
Here is your answer ⤵⤵⤵⤵⤵⤵
a = 7
d = 4
a16 = a+15d
= 7+15x4
= 7+60
= 67
S6 = n/2{2a+(n-1)d}
= 6/2{2x7+(6-1)4}
= 3{14+5x4)}
= 3(14+20)
= 3(34)
= 102
HOPE IT HELPS YOU ☺☺ !!
a = 7
d = 4
a16 = a+15d
= 7+15x4
= 7+60
= 67
S6 = n/2{2a+(n-1)d}
= 6/2{2x7+(6-1)4}
= 3{14+5x4)}
= 3(14+20)
= 3(34)
= 102
HOPE IT HELPS YOU ☺☺ !!
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