Find the 17th term from the end of the AP:1,6,11,16,_ _ _ _211,216(solution)
Answers
Answered by
22
Hi ,
Given A. P is 1 , 6 , 11 , 16 , ......, 211 , 216
Rearrange the A .P in reverse order
216 , 211 , ....... , 16 , 11 , 6 , 1
First term = a = 216
Common difference = d = a 2 - a 1 = 211 - 216 = - 5
*************************************************************************
If a and d are first term and common difference in an A . P
n th term = a n = a + ( n - 1 ) d
*****************************************************************************
Now ,
a = 216
d = -5,
n = 17
17 th term = a 17
a 17 = a + 16 d
= 216 + 16 ( -5 )
= 216 - 80
= 136
Therefore ,
Required 17 th term = 136.
I hope this will usful to you.
******
Given A. P is 1 , 6 , 11 , 16 , ......, 211 , 216
Rearrange the A .P in reverse order
216 , 211 , ....... , 16 , 11 , 6 , 1
First term = a = 216
Common difference = d = a 2 - a 1 = 211 - 216 = - 5
*************************************************************************
If a and d are first term and common difference in an A . P
n th term = a n = a + ( n - 1 ) d
*****************************************************************************
Now ,
a = 216
d = -5,
n = 17
17 th term = a 17
a 17 = a + 16 d
= 216 + 16 ( -5 )
= 216 - 80
= 136
Therefore ,
Required 17 th term = 136.
I hope this will usful to you.
******
Answered by
5
Given,
a=216 ( by reversing )
d=a2-a1=211-216= -5
a17= a+16d
a17=216+16*-5
a17=216-80
a17=136
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