Question

Find the 18th term from the last of an AP: -3, -10, -17, …….,-276​

Answer 1

Answer:

The 18 term of AP from last is -157

Step-by-step explanation:

• Arithmetic progression is the series in which the difference of the two consecutive terms of the series gives the constant value.
• nth term of an AP is given by

        $a_{n}=a+(n-1)d$

       where a is the first term and d is the common difference

Step 1of 1:

• The AP is given by -3, -10, -17, …….,-276
• Since the 18th term is calculated from the last. The first term of AP is -276.
• The common difference is given by

          $d=-10-(-17)\\d=17-10\\d=7$

• The 18 th term of AP is given by

          $a_{n}=a+(n-1)d$

             $a_{18}=-276+(18-1)7\\a_{18}=-276+(17)7\\a_{18}=-276+119\\a_{18}=-157$