find the 18th term of the AP root 2,3root 2,5 root2
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Given A.P. is √2, 3√2, 5√2, ……. First term (a) = √2 Common difference = Second term – First term = 3√2 – √2 ⇒ d = 2√2 We know that, nth term in an A. P. = a + (n – 1)d Then, 18th term of A. P. = √2 + (18 – 1)2√2 = √2 + 17.2√2 = √2 (1+34) = 35√2 ∴ 18th term of A. P. is 35√2.
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