Question

find the 19 term from the end of A.P 3,7,11.....407​

Answer 1

Answer:

a₁₉=335

Step-by-step explanation:

AP= 3,7,11.......407

d=4

On reversing the AP, we get,

407,403,399.......3

d=-4

a=407

n=19

a₁₉=a+(n-1)d

   =407+(19-1)-4

   =407-72

   =335

SO, the 19th term from the end of the AP is 335