Question

Find the 19th term of an a.p -11 ,-15 ,-19

Answer 1

Answer:

so, the 19th term is -83.

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Answer 2

19th term of AP is -83

Solution:

Given Arithmetic sequence is:

-11 , -15 , -19

The nth term of AP is given as:

$a_n = a_1+(n-1)d$

Where,

n is the term location

$a_1$ is the first term

d is common difference between terms

$d = -15 - ( - 11) = -15 + 11 = -4 \\\\d = -19 - (-15) = -19 + 15 = -4$

From sequence,

$a_1 = -11$

Therefore,

$a_n = -11 + (n - 1) \times -4$

Substitute n = 19

$a_{19} = - 11 + (19 - 1) \times - 4\\\\a_{19} = -11 - 72\\\\a_{19} = -83$

Thus 19th term of AP is -83

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