find the 2 digit multiple of 4 and the sum of them
Answers
Answered by
0
Answer:
1188
Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
First two-digit multiple of 4 will be 12.
Last two-digit multiple of 4 will be 96.
Here the series will be 12,16,20,.....,96
We know t
n
=a+(n−1)d
Thus 96=12+(n−1)4
⇒84=4n−4
⇒4n=88
⇒n=22
Sum=
2
22
(12+96)=1188
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