Question

find the 2 digit natural numbers are divisible by 6 in arithmetic progression


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Answer 1

As we know that the two digit number is from (10 to 99). So the first two digit number which is divisible by 6 is 12, second two digit number which is divisible by 6 is (12 + 6 = 18) and the last two digit number which is divisible by 6 is 96. 12, 18, 24,

Answer 2

Answer:

So the first two digit number which is divisible by 6 is 12, second two digit number which is divisible by 6 is (12 + 6 = 18) and the last two digit number which is divisible by 6 is 96. 12, 18, 24..