Question

Find the 2 number such that the difference of their square is 189 and the sum of the number is 1521.

Answer 1

Hii Mate here is Your answer,

Let the numbers be A and B and let us proceed.

A/Q : A + B = 1521 .......eq.1

A^2 - B^2 = 189 .......eq.2

Now expand eq.2 by using the identity of
a^2-b^21
A^2 - B^2 = 189

(A+B)(A-B) = 189

1521(A-B) = 189 From. eq.1

A- B = 189/1521

A - B = 0.124 ................. eq.3

Add eq.1 and 3

A+B + A-B = 0.124 + 1521

2A = 1521.124

A = 1521.124 / 2

A = 760.56

Now insert the value of A in eq. 3

760.56 - B = 0.124

B = 760.43.

Hence the value of A is 760.56 and B is 760.43. (Approx)

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