Question

Find the 2 roots of the equation x³-39x+70=0 Note: I have asked x cube not square

Answer 1

Answer:

${x}^{3} + {0x}^{2} - 39x + 70 = 0$

$\implies here \: coefficient \: of \: {x}^{3} = 1$

$\implies \: coefficient \: of \: {x}^{2} = 0$

$\implies \: coefficient \: of \: x = - 39$

$and \: the \: last \: term \: is \: constant \: term$

$\implies \: a = 1 ,b = 0,c = - 39,d = 70$

Answer 2

-2 and -5

1. x+5=0 and x+2=0
2. f(x) = -5
3. (-5)^3+39×5+70=-125+55+70
4. 0=0
5. f(x) = -2
6. same as above
7. and x-7 too if you want the full answer

answer

pavleenbhatia