Question

find the 2 solutions of the linear equation 2x-3y=12​

Answer 1

Given,

The linear equation $2x-3y=12$

We have to find the two solutions of this given equation

Let $x=0$

Substitute $x=0$ in given linear equation, we get

$2x-3y=12$

$2\times0-3y=12$

$-3y=12$

$y=-4$

Let $y=0$

Substitute $y=0$ in given linear equation, we get

$2x-3\times0=12$

$2x=12$

$x=6$

Therefore, the two solutions of give linear equation are $(0,-4)$ and $(6,0)$.

Answer 2

Given,

The linear equation 2x-3y=122x−3y=12

We have to find the two solutions of this given equation

Let x=0x=0

Substitute x=0x=0 in given linear equation, we get

2x-3y=122x−3y=12

2\times0-3y=122×0−3y=12

-3y=12−3y=12

y=-4y=−4

Let y=0y=0

Substitute y=0y=0 in given linear equation, we get

2x-3\times0=122x−3×0=12

2x=122x=12

x=6x=6

Therefore, the two solutions of give linear equation are (0,-4)(0,−4) and (6,0)(6,0) .