Question

Find the 20 term of √2, 3√2, 5√2........

Answer 1

Answer:

Hope it will help you :)

Answer 2

Answer:

$39 \sqrt{2}$

Step-by-step explanation:

here , a =

$a = \sqrt{2}$

$d = (3 \sqrt{2} - \sqrt{2)} = 2 \sqrt{2}$

so, 20 th term is = a + (n-1)d

$= \sqrt{2 } + (20 - 1) \times 2 \sqrt{2}$

$= \sqrt{2} + 19 \times 2 \sqrt{2}$

$= \sqrt{2 } + 38 \sqrt{2}$

$= 39 \sqrt{2}$