Question

Find the 200th term of the series 3 + 4 + 6 + 9 + 13 + 18 + 200 tems
- 19903
-19803
-20003
- 18903​

Answer 1

Answer:

Find the 200th term of the series 3 + 4 + 6 + 9 + 13 + 18 + 200 tems

- 19903

-19803

-20003

- 18903

Answer 2

Answer:

it's simple T=3+(n *(n-1))/2

n=200

ans=19903