find the 20th term from the last term of Ap 3,8,13,.....,253
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14
series is 3, 8, 13, ...... 253
here, first term , a = 3
common difference , d = 5
Let us find total number of terms at first.
use
=> 253 = 3 + (n - 1)5
=> 250 = 5(n - 1)
=> n - 1 = 50
=> n = 51
so, there are 51 terms in given series.
now we know, mth term from last =last term - mth term + 1
so, 20th term from last = 51 - 20 + 1 = 32
hence, 20th from last = 32th term from first
use ,
= 3 + 31 × 5 = 3 + 155 = 158
hence , 20th term from last = 158
here, first term , a = 3
common difference , d = 5
Let us find total number of terms at first.
use
=> 253 = 3 + (n - 1)5
=> 250 = 5(n - 1)
=> n - 1 = 50
=> n = 51
so, there are 51 terms in given series.
now we know, mth term from last =last term - mth term + 1
so, 20th term from last = 51 - 20 + 1 = 32
hence, 20th from last = 32th term from first
use ,
= 3 + 31 × 5 = 3 + 155 = 158
hence , 20th term from last = 158
ravirajparmar:
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Answered by
8
HOLA
========================
The given Ap is 3 , 8 , 13 ... 253
|•| To find 20th term from the last we have :
L - ( n - 1)d ==> ( Formula )
In this case , L = 253 , N = 20 , D = 5
L - (n - 1)d
253 - (20n - 1 ) 5
253 - (19n)5
253 - 95 = 158
So , 20th term from last is 158
=====================>>>
HOPE U UNDERSTAND
========================
The given Ap is 3 , 8 , 13 ... 253
|•| To find 20th term from the last we have :
L - ( n - 1)d ==> ( Formula )
In this case , L = 253 , N = 20 , D = 5
L - (n - 1)d
253 - (20n - 1 ) 5
253 - (19n)5
253 - 95 = 158
So , 20th term from last is 158
=====================>>>
HOPE U UNDERSTAND
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