Find the 20th term from the last term of the AP: 3.8.13..253.
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Answered by
2
Let,
a(first term)=3
t2(second term)=8
d(common difference)=second term - first term
=8-3
=5
20th term=a+(n-1)d
=3+(20-1)5
=3+19*5
=3+95
=98
Answered by
1
Answer:
20th term from last term is 32th term=158
Step-by-step explanation:
Here a=3, a2=8
d=a2-a
d=5
let an=253
a+(n-1)d=253
putting values
3+(n-1)5=253
n=51
so,20th term from last is 51-19=32th term
so,we have to find a32
an=a+(n-1)d
a32=3+(32-1)5
a32=3+(31)5
a32=3+155
a32=158
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