Question

find the 20th term from the last term of the ap :3,8,13.......253. ans. a32=158​

Answer 1

Answer:

$a_{32}$=158

Step-by-step explanation:

As we have to find the 20th term from last term lets take series in reverse.

So, series becomes

253,248....

a=253,d=-5

nth term of A.P.=a+(n-1)d

20th term of A.P=253+(20-1)(-5)

                           =253+(19)(-5)

                           =253-95

                           =158

So 20th term from last term of A.P is 158

Now, original series is 3,8,13..

a=3,d=5

$t_{n}$=a+(n-1)d

158=3+(n-1)5

155=(n-1)5

n-1=31

n=32

Answer 2

Answer:

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