Question

find the 20th term of an arithmetic sequence with a first term of 3 and a difference of 5

Answer 1

a = 3....

d = 5.....

20th term

= a + 19d

= 3 + 19 * 5

= 98....

Hope this helps

Answer 2

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Here is your answer
a = 3
d = 5
n = 20

As we know the formula
20th term = a + (n- 1)d
$= 3 + (20 - 1)5 \\ = 3 + 19 \times 5 \\ = 3 + 95 \\ = 98$

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