Question

Find the 20th term of the AP √2,3√2,5√2,….....​

Answer 1

Answer:

a=√2 d=2√2

T$₂₀=a+19d </p><p>=√2+2√2×19 </p><p>=√2+38√2 =39√2$

Answer 2

Answer:

39√2

Step-by-step explanation:

Here , t1=√2 ; t2 = 3√2 ; t3 =5√2

d = t2-t1

d= 3√2-√2

d=2√2

Now we have , n= 20

tn = a + ( n-1) ×d

t20 =√2 + (20-1) ×2√2

t20 = √2+ 19× 2√2

t20= √2 + 38 √2

t20 = 39 √2

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