Find the 20th term of the ap whose third term is 7 and seventeenth term exceeds 3 times the third term by 2.also find its nth term
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Answered by
1
a3=7
a+2d=7...1)
a7=3(a3)+2
a+6d=3(7)+2
a+6d=23..(2)
a+2d=7
a+6d=23
-4d=-16
d=16/4
d=4
IF d=4 THEN a=
a+2d=7
a+2(4)=7
a+8=7
a=-1
a20=a+19d
=-1+19(4)
=-1+76
=75
SO, 25th term of an AP is 75
hope it's help u
Answered by
1050
Find the 20th term of the ap whose third term is 7 and seventeenth term exceeds 3 times the third term by 2. Also find its nth term
- a3 = 7
- a + 2d = 7 ...(1)
- a7 = 3(a3) + 2
- a + 6d = 3 × 7 + 2
- a + 6d = 23 ...(2)
Now subtract (1) from (2)
- (a + 6d = 23)-(a + 2d = 7)
- = 4d = 16
So,
- 4d = 16
- d = 16/4
- d = 4
Now replace d with 4 in (1)
- a + 2 × 4 = 7
- a + 8 = 7
- a = 7 -8
- a = -1
Now,
- a20
- = a + 19d
- = -1 + 19 × 4
- = 75
Then,
- an
- = a + (n - 1)d
- = -1 + (n - 1)4
- = -1 + 4n - 4
- = 4n - 5 ans
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