Find the 20th term of the following sequence. -6, -4, -2, 0, ... 32 44 46
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tn=a+(n-1) d
t20=–6+(20–1)2
t20=–6+(19)×2
t20=–6+38
t20=32.
thus the 20th term is 32
t20=–6+(20–1)2
t20=–6+(19)×2
t20=–6+38
t20=32.
thus the 20th term is 32
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