Find the 21st term of an A.P. whose 11th term is 37 and the
26th term is 82.
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1
Answer:
181/3
Step-by-step explanation:
let the first term be a and common difference be d
since, Tn=a+(n-1)d
therefore,
a+10d=37---------→(1)
a+25d=72---------→(2)
solving (1) and (2) by subtracting them
15d=35
d=7/3
pur value of d in (1)
a=41/3
therefore,
21th term=a+20d
=41/3+20(7/3)
T=181/3
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