find the 21st term of the AP 3,10,17
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Step-by-step explanation:
We get 15 – 3, 27 – 15……
Common difference = 12
First term of series = 3.
Therefore, the 21st term of the series is
Required term after adding 120 = 120 + 243 = 363.
Let
First value of the series is a = 3
Common difference = 12
term is 363.
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