Question

find the 22 term of ap in which dequals 7 and 22 term is 149

Answer 1

Hey... 22 term is already given.... We have to find sum of 22 terms??.......

Assuming that we have to find sum,

d=7
T22=149
a+21d=149
a=149-21(7)=2

Now,
S22=22/2(2*2+21*7)
=11(151)
=1661

Answer 2

I'm assuming we have to find the sum of 22 terms

d = 7
T22 = 149
a + (n-1)d = 149
a + 21*7 = 149
a + 147 = 149
a = 2

Now
Sn = n/2 [2a + (n-1)d]
S22 = 22/2 [2*2 + (22-1)7]
= 11 [ 4 + 21*7 ]
= 11 [147 + 4]
= 11 * 151
= 1661