Question

Find the 22nd term from the last term of the AP : 3, 8, 13, . . ., 253.​

Answer 1

For the given A.P.,

First term(a)=3

Last term(t)=253

Common Difference(d)=8−3=5

=a+(n−1)d

⇒253=3+(n−1)×5

⇒253−3=(n−1)×5

⇒250÷5=n−1

⇒50+1=n

∴ n=51

In 51 terms, 22th term from the last term will be 51−22+1=30th term

=a+(30−1)d= 3 + 29 × 5 = 148

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