Question

Find the 22nd term of the arithmetic sequence 2,7,12,17

Answer 1

Answer:

Tn = a+(n-1) d

a=first term

d = common difference

n = term u need to find

T22 = 2+(22-1) 5

= 2+105

=107

d= 7-2=5

Step-by-step explanation:

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Answer 2

Answer :

107

Step-by-step explanation :

Step 1 : Find common difference

The value of each subsequent number in an arithmetic series is the most common difference. As a result, the formula for finding the common difference of an arithmetic series is

$d = a(n) - a(n - 1),$

where a(n) is the sequence's last term

 a(n - 1) is the sequence's prior term.

$d = 17 - 12$  $= 5$

Step 2 : Find the 22nd term

      $Tn = a + (n - 1)d$  

here, a = First term of the sequence,

         d = Common difference of the sequence,

         Tn = Which term to find,

    $Tn = 2 + (22 - 1) 5$

    $Tn = 2 + (21) 5$

    $Tn = 2 + 105$

    $Tn = 107$