Question

Find the 23 term of AP 100 96 92

Answer 1

$\large{\boxed{\bf{Answer}}}$

188

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Given :-

• An AP as 100, 96, 92.......

To Find :-

• 23rd term of AP.

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$\large{\boxed{\bf{Solution}}}$

• First term, a = T1 = 100

• Second term T2 = 96

∴ d = T2 - T1 = 96 - 100 = - 4

The nth term of an AP is given by :-

Tn = a + (n - 1)d

T23 = 100 + (23 - 1)(-4)

=> 100 + 22 × (-4)

=> 100 - 88

=> 12

Hence, 23rd term of AP is 12.

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Answer 2

Answer :

${\red\bigstar\Large\bold{\underline{\textsf{\green{Given:}}}}}$

• A.P. = 100, 96, 92, ...

${\red\bigstar\Large\bold{\underline{\textsf{\green{To\:Find:}}}}}$

• $\sf {23}^{rd}\:term$

${\red\bigstar\Large\bold{\underline{\textsf{\green{Sølution:}}}}}$

• First term ,

a = 100

• Common difference ,

d = 96 - 100 = -4

• Number of terms ,

n = 23

☯ Formula Used :

$\large\bold{\boxed{\boxed{\sf{\blue{ a_n\:=\:a\:+\:(n\:-\:1)d}}}}}$

➡ $\sf {a}_{23}\:=\:100\:+\:(23\:-\:1)-4$

➡ $\sf {a}_{23}\:=\:100\:+\:(22)-4$

➡ $\sf {a}_{23}\:=\:100\:-\:88$

➡ $\sf {a}_{23}\:=\:12$

☯ $\large\bold{\boxed{\sf{\pink{ {a}_{23}\:=\:12}}}}$

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