Question

Find the 23rd team of AP whose 7th terme
is 24 less than the 11th term, first
term being 12.​

Answer 1

Answer:

144 is the correct answer

Step-by-step explanation:

given: a=12

11th - 7th = 24

(a+10d)-(a+6d) = 24

4d=24

d=6

now, 23rd term = a+22d

a=12 and d=6

so, a+22d = 12 + 22(6)

= 12 + 132 = 144

Answer 2

Answer:

The 23rd term of the A.P = 144

Step-by-step explanation:

Given:

• First term of the A.P = 12
• 7th term = 24 less than 11th term

To Find:

• The 23rd term of the A.P

Solution:

Given that the first term of the A.P is 12 = a₁

Also by given,

7th term = 11th term - 24

The nth term of an A.P is given by,

aₙ = a₁ + (n - 1) × d

where n is the number of terms and d is the common difference

Hence,

a₇ = a₁₁ - 24

a₁ + 6d = (a₁ + 10d) - 24

Substitute the value of a₁,

12 + 6d = (12 + 10d) - 24

12 + 6d = 10d - 12

24 = 4d

d = 6

Hence common difference of the A.P is 6.

Now the 23rd term of the A.P is given by,

a₂₃ = a₁ + 22d

Substitute the value of a₁ and d,

a₂₃ = 12 + 22 × 6

a₂₃ = 12 + 132

a₂₃ = 144

Therefore 23rd term of the A.P is 144.