Find the 23rd term of 2,4,6,8,...
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2
Hii ☺!!
AP = 2 , 4 , 6 , 8 .....
Here,
First term ( a ) = 2
Common difference ( d ) = 4 - 2 = 2
Therefore,
23rd term of the given AP = a + 22d = 2 + 22 × 2 = 2 + 44 = 46 .
AP = 2 , 4 , 6 , 8 .....
Here,
First term ( a ) = 2
Common difference ( d ) = 4 - 2 = 2
Therefore,
23rd term of the given AP = a + 22d = 2 + 22 × 2 = 2 + 44 = 46 .
Answered by
0
a = 2
d = 2
Tn = a + (n-1)d
T23 = 2 + (23 - 1)2
T23 = 2 + (22)2
T23 = 2 + 44
= 46
23 rd Term is 46
d = 2
Tn = a + (n-1)d
T23 = 2 + (23 - 1)2
T23 = 2 + (22)2
T23 = 2 + 44
= 46
23 rd Term is 46
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