Question

find the 23rd term of an ap whose 7th term is 24 less than the 11th term find one term being 12​

Answer 1

Answer:

Answer

Given ,

First term =a=12

Let the common difference be d

and we know 7th term a

7

=a+6d

and 11th term a

11

=a+10d

According to question ,

a

11

−a

7

=24

a+10d−(a+6d)=24

a+10d−a−6d=24

4d=24

d=6

We know that,

20th term =a

20

=a+19d=12+19(6)=12+114=126

So , the 20th term of AP is 126.

Answer 2

Answer:

2o th term of Ap is 126

Step-by-step explanation:

given

A =12

find 20 term

therefore..

according to the statement

(a+ 6d) - (a-10d) = 24

a+10d-a-6d=24

d=6

now 20 th term

a+19d

=12+19(6)

12*114

=126..