Question

find the 24th term and sum of 50 terms of the Ap 3,7,11​

Answer 1

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$\bf\bold\pink{\boxed{MARK\:AS\:BRAINLIEST}}$

Answer 2

$\rm AP=3 \ , \ 7 \ , \ 11 \ ,\ ........\\\\\rm Common \ difference =7-3=4\\\\\bf\boxed{ \rm\bf x_{n} = a+(n-1)d}\\\\\rm x_{24}=7+(24-1)4\\\\\rm x_{24} = 7+23 \times 4\\\\\rm\bf\underline{ x_{24}=99}$

24th term = 99

$\rm x_{50}=7+(50-1)4\\\\\rm x_{50}=7+49 \times 4\\\\\rm\bf x_{50}=203$

$\bf \boxed { \rm\bf Sum \ of \ first \ n \ terms = \dfrac{n}{2} \times (x_{n}+x_{1})}\\\\\\\rm Sum \ of \ first \ 50 \ terms = \dfrac{50}{2} \times (203+3)$

                               $\rm = 25\times 206$

                               $\rm\bf = 5150$

HOPE IT HELPS U  :)