Question

find the 25 term of an a.p which nth term is given by tn=(7-3n)

Answer 1

Tn = 7 - 3n

=> a + (n-1) d = 4 + 3 - 3n

=> a + (n-1) d = 4 - 3 (n-1)

On Comparing both sides, we get

a = 4

d = - 3

=> T25 = a + 24d

=> T25 = 4 + 24(-3)

=> T25 = 4 - 72

=> T25 = - 68

Answer 2

Thus so

THUS GIVEN
➡ Tn = 7 - 3n

THEN IF n = 1
. THEN A = 7 - 3
. 4

. IF n = 2
. THEN A 2 = 7 - 6
. 1

. THEN D = 1 - 4
. - 3

. THE 25 TH TERM
. A + 24 D
. 4 + 24 * - 3
. 4 - 72
. - 68

. Hope it helps

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