find the 25 term of an AP: 2,6,10,14
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Answer:
the 25th term is 98
Step-by-step explanation:
here AP is 2,6,10,14,...
common difference (d) = t₂ - t₁
d = 6 - 2
d = 4
first term (a) = 2
nth term of an AP,
tₙ = a + (n-1)d
t₂₅ = 2 + (25-1) 4
t₂₅ = 2 + (24 x 4)
t₂₅ = 2 + 96
t₂₅ = 98
∴ the 25th term is 98
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