Question

Find the 25th term of an Arithmetic progression 2,6,10,14​

Answer 1

the 25th term is 98

Step-by-step explanation:

AP :- 2,6,10,14

a = 2

d = 6-2 = 4

a25 = a + 24d = 2+24(4) = 2+96 =98

Answer 2

We are given an A.P: 2,6,10,14,...

In the given A.P, we know that:

⇒ First term(a) = 2

⇒ Common difference (d) = 6-2 = 4

We know that the nth term of an A.P. is generalized by:

⇒ aₙ = a+(n-1)d

Similarly, 25th term of an A.P is:

⇒ a₂₅ = a+(25-1)d

⇒ a₂₅ = a+24d

By substituting a and d in a+24d, we get:

⇒ a₂₅ = 2+24×4

⇒ a₂₅ = 2+96

⇒ a₂₅ = 98

Hence, the 25th term of the A.P is 98.

Know more:

The general form of A.P is given by,

⇒ a, a+d, a+2d, a+3d,...