Question

find the 25th term of the a.p 100,96, 92 88

Answer 1

Solution:-
In the given AP,
a = first term = 100
d = common difference = 96 - 100 = - 4
So, 25th term is, 
t₂₅ = a + (n - 1)d
= 100 + (25-1) (- 4)
= 100 + (24 × -4)
= 100 - 96
t₂₅ = 4 
Answer.

Answer 2

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$\huge{given}$

$\bold{ap \: = 100 ,\: 96, \: 92, \: 88}$

$a = 100 \\ d = 96 - 100 \\ \: \: \: \: = - 4 \\ t_{25} = ? \\ n = 25$
$t_{25} = a + (n - 1)d \\ \: \: \: \: \: \: = 100 + (25 - 1) - 4 \\ \: \: \: \: \: \: = 100 + 24 \times ( - 4) \\ \: \: \: \: \: = 100 - 96 \\ \: \: \: \: \: = 4$

$\huge{Answer \: = \: 4}$

✌hope it helps u ✌

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