Question

Find the 25th term of the A.P.-5,-5/2,0,5/2…?

Answer 1

Here your answer

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First term T1= - 5

Difference between term = - 5/2-(-5)=5-5/2=5/2




Formula of nth term


Tn= T1+ (n-1)d


T25 = - 5 + ( 25-1)(5/2)

= - 5 + 24(5/2)

= - 5 + 60

= 55...your answer

Hope it helps you

Answer 2

a25 = ?

a1 = - 5

a2 = - 5/2

a3 = 0

a4 = 5/2

Here, to find d,

d = a2 - a1

d = -5/2 - (-5)

d = -5/2 + 5

d = ( - 5 + 10)/2

d = 5/2

Therefore,

a1 = - 5, d = 5/2, n = 25

an = a+ ( n-1) d

a25 = - 5 + (25 - 1) 5/2

a25 = - 5+ ( 24) 5/2

a25 = - 5 + 12* 5

a25 = -5 + 60

a25 = 55

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