Question

Find the 25th term of the AP -5, -5/2, 0, 5/2........​

Answer 1

Answer:

applying formula

applying formula an=a+(n-1) d

applying formula an=a+(n-1) da= first term

applying formula an=a+(n-1) da= first termd=last term

applying formula an=a+(n-1) da= first termd=last termso

applying formula an=a+(n-1) da= first termd=last termsoa=-5

applying formula an=a+(n-1) da= first termd=last termsoa=-5d=2.5

applying formula an=a+(n-1) da= first termd=last termsoa=-5d=2.5applying on formula

applying formula an=a+(n-1) da= first termd=last termsoa=-5d=2.5applying on formula 25=-5+(25-1) 2.5

applying formula an=a+(n-1) da= first termd=last termsoa=-5d=2.5applying on formula 25=-5+(25-1) 2.525=-5+(24) 2.5

applying formula an=a+(n-1) da= first termd=last termsoa=-5d=2.5applying on formula 25=-5+(25-1) 2.525=-5+(24) 2.525=-5+(24) 2.5

applying formula an=a+(n-1) da= first termd=last termsoa=-5d=2.5applying on formula 25=-5+(25-1) 2.525=-5+(24) 2.525=-5+(24) 2.525=-5+(60)

applying formula an=a+(n-1) da= first termd=last termsoa=-5d=2.5applying on formula 25=-5+(25-1) 2.525=-5+(24) 2.525=-5+(24) 2.525=-5+(60) 25=55

applying formula an=a+(n-1) da= first termd=last termsoa=-5d=2.5applying on formula 25=-5+(25-1) 2.525=-5+(24) 2.525=-5+(24) 2.525=-5+(60) 25=55the 25 th term is 55