Question

Find the 26th terms of the A.P : 10,6,2,-2,-6,-10,..?
(a) -86
(b) -96
(c) -90
(d) -106​

Answer 1

Answer:

(c) -90

Step-by-step explanation:

first term (a) = 10

difference (d) = a2 - a1 = 6 - 10

difference (d) = -4

term (n) = 26

26th term = a + (n - 1) × d

26th term = 10 + (26 - 1) × -4

26th term = 10 + 25 × -4

26th term = 10 - 100

26th term = -90

Answer 2

Answer:

The correct option is (c) is :- -90

Step-by-step explanation:

$\bf \underline{Solution-}$

Let us consider the last terms this first term 'T'

∴ a = 10

d = 6 - 10

= -4

∴ Tₙ = a + (n - 1 ) d

Putting the value in formulae

→ T₂₆ = 10 + (26 - 1) -4

→ T₂₆ = 10 + 25 × (-4)

→ T₂₆ = 10 - 100

→ T₂₆ = -90

Answer:

Hence, the 26th terms of the A.P : 10,6,2,-2,-6,-10,.. is -90

Used Formulae:

Tₙ = a + (n - 1 ) d

Where,

a = first term

d = Common different