find the 27th term of A.P whose 6th term is 19 and 17th term is 41.
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Step-by-step explanation:
Tn=a+(n−1)d
Where a is the first term, d is the common difference and Tn denotes the n-th term of an AP.
Given:
19=a+5d
41=a+16d
Solving the above equations gives: d=2,a=9
T27=9+26×2=9+52=61
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hi @vinayreddy63
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