find the 27th term of the AP root x, 3 root x, y root x
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√x,3√x,y√x is in AP
a=√x,d=3√x-√x
d=2√x
Tn= a+(n-1)d
T27=√x+(27-1)2√x
=√x+52√x
=53√x
therefore the 27th term is 53√x
a=√x,d=3√x-√x
d=2√x
Tn= a+(n-1)d
T27=√x+(27-1)2√x
=√x+52√x
=53√x
therefore the 27th term is 53√x
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