Question

Find the 29th term of AP whose second term is 2 and fifth term is -37...

Answer 1

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Answer:

It is given that

a2=2

a5= -37

We have to find a29,

We know that

Second term,a2= a+d

And fifth term,a5= a+4d

Now,

a+d=2---------equation (1)

a+4d= -37-----------equation (2)

Subtracting (2) from (1),

-3d= 39

-d= 13

d= -13

Substituting d= -13 in eq(1),

a+(-13)=2

a-13=2

a= 2+13

a=15

Now, 29th term,a29= a+28d

Substituting a=15 and d= -13,

a29= 15+28(-13)

a29= 15-364

a29= -349

Therefore, 29th term= -349

Answer 2

Answer:

-349

Step-by-step explanation:

a+d=2

a+4d=-37

By subtracting and applying values...

We get a=15 and d=-13

Therefore, 29th term=a+28d

=-349