find the 2number x&y whose sum is16, sum of whose cubes is minima
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We have to maximise x³ +y³ and we have x+y=16
Put x=16−y in x³ +y³
we get f(y)=48y² −768y+4096
First derivative is given by
f (y)=96y−768
Putting this to zero we get, y=8
f (y)=96
Given that second derivative is positive
So given function will have minima when y=8
So x=16−8=8
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