find the 2x square +x-6=0 by factorization
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Answered by
1
Step-by-step explanation:
2x^2+x-6=0
2x^2+4x-3x-6=0
2x(X+2)-3(X+2)=0
(X+2)(2x-3)=0
X+2=0 or 2x-3=0
X= -2 or 2x=3
x=-2 or X=3/2
Answered by
1
Step-by-step explanation:
2x²+x-6=0
multiply last term with first term
so -6×2x²=-12x²
now find factors of -12x²when which multiplied we get -12x² and when sub of
add we get x
factor=4x(‐3x)
so now substitute this factor in the place of middle term
2x²+4x(‐3x)‐6=0
2x(x+2)‐3(x+2)=0
so (x+2),(2x‐3) =0
if (x+2)=0 then x=(‐2)
or
if(2x‐3)=0 then 2x=3
x=3/2
thank you ☺️
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