Find The
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Ја о 0 es
긔 닌
9
(Б, 3,3
S Ч
9
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0
Answer:
The numbers A28,3B9,62C are divisible by k
Let A28=ka,3B9=kb,62C=kC where a,b,c are integers
Let Δ=∣∣∣∣∣∣∣∣A8239B6C2∣∣∣∣∣∣∣∣
=∣∣∣∣∣∣∣∣A(8+100A+10.2)23(9+100.3+10.B)B6(C+100.C+10.2)2∣∣∣∣∣∣∣∣
→ [ By (R2+100R1+10R3)]
=∣∣∣∣∣∣∣∣AA28233B9B662C
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Answer:
good afternoon
Step-by-step explanation:
have a nice day ahead
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