Math, asked by kuljeetsingh200294, 6 months ago

Find The
3
Ел) с 5L
Ја о 0 es
긔 닌
9
(Б, 3,3
S Ч
9​

Answers

Answered by madhukahr
0

Answer:

The numbers A28,3B9,62C are divisible by k

Let A28=ka,3B9=kb,62C=kC where a,b,c are integers

Let Δ=∣∣∣∣∣∣∣∣A8239B6C2∣∣∣∣∣∣∣∣

=∣∣∣∣∣∣∣∣A(8+100A+10.2)23(9+100.3+10.B)B6(C+100.C+10.2)2∣∣∣∣∣∣∣∣

→ [ By (R2+100R1+10R3)]

=∣∣∣∣∣∣∣∣AA28233B9B662C

Answered by SanchitaHatture
1

Answer:

good afternoon

Step-by-step explanation:

have a nice day ahead

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