Question

find the 3 consecutive no.whose sum is183.

Answer 1

Let the numbers be a, a+1 and a + 2

According to question,

a + a + 1 + a + 2 = 183

=> 3a + 3 = 183

=> 3a = 180

=> a = 60

First number = 60

Second number = 61

Third number = 62

Answer 2

let the first no. be x
then,the other two are x+1,x+2 respectively
according to the question, x+x+1+x+2=183
3x+3=183
3x=183-3
3x=180
x=180/3
x=60
then the other two no. are
x+1=60+1=61
x+2=60+2=62
HOPE IT HELPS YOU
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