Question

find the 3 consecutive terms in an A.P whose sum is -3 and the product of their cube is 512​

Answer 1

Answer:

Step-by-step explanation:

(a-d) + (a) + (a+d ) = -3

3a= -3

a= -1

(a-d)^3 x  a^3 x (a+d)^3 = 512

{(a-d)(a+d)(a) } ^3 = 512

{ (a^2 - d^2 )(a) } = 8

1 - d^2 = -8

d^2 = 9

d = +-3

when d = 3

ap = -4,-1 , 2

when d = - 3

ap = 2,-1,-4